Today Puzzle #740
Puzzle No. 740鈥� Friday 15 May
At a meeting of coin collectors, every person has a collection of one, five and ten pence coins. Every coin collector has fifty coins in their pocket that when added together give a total of one pound. If no two people brought the same combination of 1p, 5p and 10p coins, what is the largest possible number of people at the meeting?
Today’s #PuzzleForToday has been set by Dr Steve Humble from Newcastle University
Click here for the answer
There would be only 1 coin collector at the meeting with a combination of two 10ps, eight 5ps and forty 1ps.
Details of a possible solution are
M+5N+10P=100
M+N+P=50
subtracting these gives 4N+9P=50 which has only one integer solution for our puzzle.
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